0.49x^2=0.28x-0.04

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Solution for 0.49x^2=0.28x-0.04 equation:



0.49x^2=0.28x-0.04
We move all terms to the left:
0.49x^2-(0.28x-0.04)=0
We get rid of parentheses
0.49x^2-0.28x+0.04=0
a = 0.49; b = -0.28; c = +0.04;
Δ = b2-4ac
Δ = -0.282-4·0.49·0.04
Δ = 1.3877787807814E-17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.28)-\sqrt{1.3877787807814E-17}}{2*0.49}=\frac{0.28-\sqrt{1.3877787807814E-17}}{0.98} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.28)+\sqrt{1.3877787807814E-17}}{2*0.49}=\frac{0.28+\sqrt{1.3877787807814E-17}}{0.98} $

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